This model issue tells the best way to track down the energy of a photon by its frequency. To do this, you want to utilize the wave condition to relate frequency to recurrence and Planck’s condition to track down energy. This sort of issue is a great practice to modify conditions, utilize the right units, and track huge figures.
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To tackle this issue you want to utilize two conditions:
The first is Planck’s condition, which was proposed by Max Planck to portray how energy is moved in quanta, or bundles. Planck’s condition makes it conceivable to figure out blackbody radiation and the photoelectric impact. The condition is:
E = Hν
where
e = energy
h = Planck’s consistent = 6.626 x 10-34 J s
= recurrence
The subsequent condition is the wave condition, which depicts the speed of light regarding frequency and recurrence. You utilize this condition to settle for the recurrence you plug into the primary condition. The wave condition is:
= frequency
= recurrence
Revamp the condition to settle for recurrence:
= c/
Then, supplant the recurrence in the primary condition with c/λ to get a recipe you can utilize:
E = Hν
E = HC/
As such, the energy of a photo is straightforwardly relative to its recurrence and conversely corresponding to its frequency.
All that is left is to connect the qualities and find the solution:
E = 6.626 x 10-34 J s x 3 x 108 m/s/(633 Nm x 10-9 m/1 Nm)
Reply:
The energy of a solitary photon of red light from a helium-neon laser is 3.14 x – 19 J.
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Energy Of One Mole Of Photon
While the primary model tells the best way to find the energy of a solitary photon, a similar strategy can be utilized to track down the energy of one mole of a photon. Fundamentally, what you do is track down the energy of a photon and duplicate it by Avogadro’s number.
A light source transmits radiation with a frequency of 500.0 nm. Track down the energy of the one-mole photon of this radiation. Express the response in units of kJ.
A unit transformation should be finished on the frequency and incentive for the situation to work. In the first place, convert nm to m. Nano – is 10-9, so you should simply move the decimal spot 9 places or gap by 109.
The last worth is the frequency communicated utilizing logical documentation and the right number of critical figures.
Recall how Planck’s condition and wave condition were consolidated to give:
E = HC/
E = (6.626 x 10-34 J s) (3.000 x 108 m/s)/(5.000 x 10-17 m)
E = 3.9756 x 10-19 J
Be that as it may, this is the energy of a solitary photon. Increase the worth by Avogadro’s number for the energy of one mole of the photon:
The energy of one mole of photon = (energy of single-photon) x (Avogadro’s number)
The energy of one mole of photon = (3.9756 x 10-19 J) (6.022 x 1023 mol-1) [Hint: increase the decimal numbers and afterward deduct the denominator example from the numerator type to get the force of 10)
Energy = 2.394 x 105 J/mol
For one mole, the energy is 2.394 x 105 J. Is
Note how the worth holds the right number of critical figures. It actually should be changed over from J to kJ for the last response:
Energy = (2.394 x 105 J) (1 kJ/1000 J)
Energy = 2.394 x 102 kJ or 239.4 kJ
Keep in mind, in the event that you really want to do extra unit changes, actually take a look at your critical digits.